Mark Dalen

Should be:
G = (cos(a) + sin(a))/(1-cos(a))

Not:
G = (cos(a) - sin(a))/(1-cos(a))

I had it right on the paper, but my fingers failed.

John/TSR

Showoff.

Mark Dalen

I'm good at worthless math. It works when the angle is trivial and fails the reality test when the banking is significant.

Have I told you my theroy about g-sum?
How about driver suit color?

ryoung

and thanks for saving the day :-)

LCP

...they didn't seem to care, and left my score at 770 instead of 800. We're more understanding here; you get full credit.

LCP

Not (1-COS(a)) -- that is if cosine is adjacent side over hypotnuse, and sine is opposite side over hypotnuse, correct? This is the case at least as to how Excel is computing it.

This also gets me to thinking that cosine should be replaced with a tangent function, as the radius of a corner would normally ignore banking (the hypotnuse), correct?

Mark Dalen

Though this is mental masturbation because (again) the change in tire characteristics is so big, it destroys this equation matching reality.

But, the component you are talking about is the downward component of the lateral G so I think you are right. It would also take a bit more thought to be sure whether G is horizontal to the earth or the track.

s4wood

I squeeked out with a C- in both of them..never to look back.

Mark Dalen

So sometimes this junk leaks back in. I'll try harder...

My name is Mark and I'm an Engineer.

LCP

Dude, this is just geometry and algebra, with a dash of racing physics, from high school. ;-)